Question

p(x)=7x2+6x-1;q(x)=6x-9​

Answer 1

Answer:

$q(x) = 6x - 9 = 0 \\ 6x = 9 \\ x = \frac{9}{6} \\ \boxed{x = \underline{ \underline{ \frac{3}{2} }}} \\ \\ p(x) = 7 {x}^{2} + 6x - 1 \\ p( \frac{3}{2} ) = 7 {( \frac{3}{2}) }^{2} + (6 \times \frac{3}{2} ) - 1 \\ = (7 \times \frac{9}{4} ) + 9 - 1 \\ = \frac{63}{4} + 8 \\ = \frac{63 + 32}{4} \\ = \frac{95}{4} \\ \large{ \boxed{= \underline{ \underline{ 23 \frac{3}{4} }}}}$