Math, asked by anubrotobhowmick2006, 10 months ago

p(x)= 8x³- 6x² - 4x + 3 g(x)= x/3 -1/3 is this a factor of polynomial

Answers

Answered by vanshagarwal12qwer
3

Answer:

g(x) = x/3-1/3= (x-1)/3=x-1.

remainder is 0 means g(x) is a factor of p(x) .

so if we divide p(x) by g(x).

{ 8x cube -6x square -4x +3} ÷ {x-1}

quotient is 8x square -2x -2 .

remainder is 1.

so, the given g(x) is not a factor of p(x)

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Answered by fatimashaikh28950
0

Answer:g(x) = x/3-1/3= (x-1)/3=x-1.

remainder is 0 means g(x) is a factor of p(x) .

so if we divide p(x) by g(x).

{ 8x cube -6x square -4x +3} ÷ {x-1}

quotient is 8x square -2x -2 .

remainder is 1.

so, the given g(x) is not a factor of p(x)

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