p(x)=9x²-4,find zeroes of the polynomial with explanation
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Answer:
p(x) = 9x² -x
to get zeroes, put the poly. =0
so,
9x²-x=0
x(9x-1)=0
hence,
x=0 or 9x-1=0
=> x=0 or x=1/9
therefore, the 2 zeroes r
0, 1/9
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