P( x ) = a square + bx + c if a +b +c =0 then find one of its zero [PUT X=1 then, P(X)=0
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Answer:
x=1 is the root of p(x)
Step-by-step explanation:
P(x ) = ax² + bx + c
put x = 1
P(1) = a + b + c
but a + b + c = 0
so, P(1) = 0
so, x = 1 is the root of P(x )
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