Math, asked by kanishkkhare12, 8 months ago

p(x)= ax +b;a does not =0,a,b are real numbers​

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Answered by mismarttv94
0

Answer:

Find a zero of the polynomial p(x)=ax+b,ane0 and a , b are real numbers. ... The roots of `ax^(2)+bx+c=0,. play. 1:07 · The value(s) of ... 40. a, b, c are non-zero real numbers such that a. play. 2:18 · Given is a polynomial polynomial.`x^(3)-6x^(.

Step-by-step explanation:

Answered by shashiawasthi069
0

Step-by-step explanation:

p(x)= ax +b;a does not =0

ax+b = 0

ax = -b

x = -b/a

this is linear equation of one variable

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