p(x)=ax+b;x=-a/b
verify whether the value of x given in each case are the zeros of the polynomial or not
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Answer:
putting x = -a/b , we get ,
p(x)= a × (-a/b) +b
= -a²/b +b
on taking LCM we get
p(x)= -a²+b²/ b
now as -a²+b²/b is not zero so given value of x is not
a zero for the given polynomial p(x)
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