p(x) =ax2+bx+c and a+b+c=O, then one of the zero
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Answer:
(x-1) is a factor
Step-by-step explanation:
put x=1 in p(x)
a( (1)^2 ) + b(1) + c = a+b+c
a+b+c = 0 (given)
hence, p(1) = 0
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