p(x)=ax2+bx+c, if a+b+c=0, then find one of its zero
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Answer:
Step-by-step explanation:
P(x ) = ax² + bx + c
put x = 1
P(1) = a + b + c
but a + b + c = 0
so, P(1) = 0
so, x = 1 is the root of P(x )
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