P(x)Cx+d,c=not 0 and c,d are real number
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Answer: -d/c
Step-by-step explanation:
p(x)=cx+d
p(x)= 0 ( as we have to find the zero of the polynomial p(x))
so,
cx+d=0 (as p(x)=0)
cx=-d
x=-d/c
now inserting -d/c in the above given polynomial
so,
p(-d/c)=c x (-d/c) +d
p(-d/c)= -d+d (as c gets cancelled by the c in division )
p(-d/c)=0 (as -d got cancelled by +d)
so,
after the whole calculation -d/c is the zero of the polynomial p(x).
Hope, it helps
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