Math, asked by bandnad780, 1 month ago

p(x) = k(x)^2-3x+k
put 1 in all x ​

Answers

Answered by shailik39
1

Answer:

p(x) = k (1) ^2 - 3 ( 1) + k = 0

k - 3 + k = 0

2k - 3 = 0

2k = 0 + 3

k = 3/2

the value of k is 3 / 2

Answered by diya155731
0

Step-by-step explanation:

p(x)= k(x)^2 -3x +k

= k(1)^2 -3(1)+k

= 2k-3+k

=0

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