Question

p(x)=kx^3+x^2-22x-21. (x+3)​

Answer 1

Answer:

2=k

Step-by-step explanation:

x+3=0

x=-3

p(x)=k(-3)^3+(-3)^2-22(-3)-21

0=-27k+9+66-21

0=-27k+54

-54=-27k

-54/-27=k

2=k

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Answer 2

Heya mate!⬛

p(x)=kx^3+x^2-22x-21

x+3=0

x=-3

Putting the value of x =-3 in p(x)

k into (-3)^3+(-3)^2-22 into (-3) -21

k into -27 +9 + 66 -21 =0

-27 k +54 = 0

-27 k=-54

k=-54 upon -27

k=2

hope it helps you. plz mark as brainliest