Question

p(x)=kx square -3xpluse 1​

Answer 1

Answer:

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Step-by-step explanation:

If x−1 is the factor of the equation then put x=1 in these equation

(i) x

2

+x+k=0⇒(1)

2

+1+k=0⇒1+1+k=0⇒k=−2

(ii) 2x

2

+kx+

2

=0⇒2(1)

2

+k(1)+

2

=0⇒2+k+

2

=0⇒k=−2−

2

(iii) kx

2

−

2

x+1=0⇒k(1)

2

−

2

(1)+1=0⇒k−

2

+1=0⇒k=

2

−1

(iv) kx

2

−3x+k=0⇒k(1)

2

−3(1)+k=0⇒k−3+k=0⇒2k=−3⇒k=−

2

3

Answer 2

Step-by-step explanation:

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