Math, asked by gillharmanjot45, 8 months ago

p(x) = kx² - √2x 1 . find the value of k if x is 1​

Answers

Answered by mayukhsaha18
3

Answer:

k=1+root2

Step-by-step explanation:

p(x)= kx^2-root2x

replacing x with 1

p(1)=k*1^@ - root2*1

=k-root2=1

k=1+root2

Answered by sethanand272
3

Step-by-step explanation:

p(x)=kx²-√2x+1

=k-√2+1=0

k=√2-1

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