Math, asked by dhruvibamania, 21 hours ago

p(x)= kx²-√2x+1
give me right answer​

Answers

Answered by xXItzVillainxX
0

p(x) =  {kx}^{2}  -  \sqrt{2x} + 1 \\ replacing \: the \: value \: of \: x \: as \: 1 \\  \\  = k -  \sqrt{2}  + 1 = 0 \\ k =  \sqrt{2}  + 1

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