Question

p(x) = kx3 + 3x2 - 3 ,q(x) = 2x3 - 5x + k When divided by x-4 leave the same reminder in each case, find the value of k... Please answer the question....PLEASE

Answer 1

Answer:

$\huge \textcolor{red}{k=1}$

Step-by-step explanation:

Put x=4 in both equations. The value you get is the remainder.

$</p><p>p(4)=k(4)^3+3(4)^2-3\\</p><p>p(4)=\text{Remainder}=64k+3\times 16-3\\</p><p>=64k+45\\</p><p>q(4)=2(4)^3-5(4)+k\\</p><p>q(4)=108+k\\</p><p>\text{Since remainders are same,}\\</p><p>108+k=64k+45\\</p><p>63k=63\\</p><p>k=1$