Question

P(x)=kx3+9x2+4x-10 devided by x-3

Answer 1

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Hi,friend!!✌

●●●A good question you have asked.●●

Here is your answer.

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If , p(x)= kx³+9x²+4x-10

Then, p(-3) = 5 [ By the remainder theorem x-(-3)]

So, k(-3)³+9(-3)²+4(-3)-10 = 5

=> -27k + 81 - 12 -10 = 5

=> -27k + 81 = 5 + 10 + 12

=> -27k= 27-81

=> k = -54\-27

=> k = 2

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◇◇◇Hope you will understand this math◇◇