Math, asked by kvinay26094, 2 months ago

p(x)×q(x) p(x)=x²+4x+8 एवं q(x)=x²-4x+8​

Answers

Answered by nandinivarma2004
0

Answer:

x2+64

Step-by-step explanation:

p(x) = x2+4x+8 and q(x) = x2-4x+8

p(x) × q(x) = (x2+4x+8)(x2-4x+8)

= (x2.x2)+(x2.-4x)+(x2.8)+(4x.x2)+(4x.-4x)+(4x.8)+(8.x2)+(8.-4x)+(8.8)

=(x4-4x2+8x2+4x3-16x2+32x+8x2-32x+64)

=(x4-4x2+4x2+8x2-16x2+8x2+32x-32x+64)

cancelling the plus and minus terms

we get

=(x4+64)

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