p(x)= t^3-1 find the value of p(-6)
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(NOTE: In the given question ;the function
p(x)=t³-1 , in this function there no variable of x , so for the values of x ,
p(x)=t³-1; so p(-6)=t³-1
If: The function becomes p(x)=x³-1 assuming that there was an error in the previous in the question , then the solution below can be followed;)
→So the question becomes a function p(x)=x³-1 , find p(-6)?
Given:
p(x)=x³-1
To find:
p(-6)=?
Solution:
To find p-6)
put -6 in place of x in function p(x)=x³-1
p(-6)=(-6)³-1 ; (-6)³=-210
=-210-1
=-211
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