Question

p (x) = (x-1) (x+1)​

Answer 1

Explanation:

p(x) = (x-1)(x+1)

So the zero of the polynomial has 2 cases.

Case 1 : (x-1) = 0

=> x = 1

Case 2 : (x+1) = 0

=> x = (-1)

Therefore the zeroes of yhe polynomial are 1 and -1 and the polynomial is x^2 - (1)^2 (By using (a+b)(a-b) = a^2 - b^2)

Answer 2

Answer:

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