Math, asked by gaganganesh377, 2 months ago

p(x) = (x-1) (x+1) at p (0), p (1), p (2)l​

Answers

Answered by archanamanasam
0

Step-by-step explanation:

p(0)=(0-1)(0+1)

p(1)=(1-1)(1+1)

p(2)=(2-1)(2+1)

Now you can find it.

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