Question

p(x) =(x-1) (x+1): find p(0) p(1) p(2) polynomials grade 9th​

Answer 1

Step-by-step explanation:

P(X)=(x-1)(x+1)

by Identity We Can Say That (x-1)(X+1)=x²-1²=x²-1

P(x)=x²-1

now

p(0)=0²-1=-1

p(1)=1²-1=0

p(2)=2²-1=4-1=3

Hope That Helps

Answer 2

Answer:

Let x=0

P(0) =(0-1)(0+1)

=(-1)(1)

=-1

Let x=1

P(1)=(1-1)(1+1)

=(0)(2)

=0

Let x=2

P(2)=(2-1)(2+1)

=(1)(3)

=3