Question

P(x)=(x-1)(x+1)
P(0),P(1),P(2)

Answer 1

This is simple. All you have to do is to just put values of 'x' as 0,1,2.

p(0) = (0-1)(0+1) =-1(1) = -1

p(1) = (1-1)(1+1)= 0

p(2) = (2-1)(2+1)= 1(3)= 3

Answer 2

➡️p(0) = (0-1) (0+1)

= -1

➡️p(1) = (1-1)(1+1)

=0

➡️p(2) = (2-1)(2+1)

=3

$hope \: its \: help \: u$

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