p(x)=(x-1)(x+1);x=-1,-2 verify whether the values of x given in each case are the zeros of the polynomial or not?
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Step-by-step explanation:
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x= (-1) is a zero of polynomial (x-1)(x+1) but x= (-2) is not a zero of polynomial (x-1)(x+1).
Step-by-step explanation:
x= (-1)
P(x)= (x-1)(x+1)
P(-1)= (-1-1)(-1+1)
P(-1)= (-2)(0)
P(-1)= 0
Therefore, x= (-1) is a zero of polynomial (x-1)(x+1)
x= (-2)
P(x)= (x-1)(x+1)
P(-2)= (-2-1)(-2+1)
P(-2)= (-3)(-1)
P(-2)= 3
Therefore, x= (-2) is not a zero of polynomial (x-1)(x+1)
Hope this helps you!
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