Question

p(x) =(x-1) (x+2),x=-1,-2​

Answer 1

Answer:

p(-1) and p(-2) = 0

Step-by-step explanation:

p(x) = (x + 1)(x + 2)

= x² + 2x + x + 2

p(x) = x² + 3x + 2

at x = -1

p(-1) = (-1)² + 3(-1) + 2

= 1 - 3 + 2

= 3 - 3

= 0

at x = -2

p(-2) = (-2)² + 3(-2) + 2

= 4 - 6 + 2

= 6 - 6

= 0

Answer 2

Step-by-step explanation:

⚫(x-1)(x+2)

⚫x^2 +2x-x-2

⚫x^2+x-2 (this is an quadratic EQ. of the following factors....)

so,

⚫x^2+2x-x-2

⚫x(x+2)-1(x+2)

⚫(x-1)(x+2) [as given in the question]

✔x-1=0

x=+1

✔x+2=0

x=-2

Thanks u ❤