Question

{P}(x)=(x-1)(x-2)(x-3)

Answer 1

Answer:

To find zeroes , P(x) = 0

(x-1)(x-2)(x-3)= 0

x-1 = 0 ; x = 1

x-2 = 0 ;  x = 2

x-3 = 0 ;  x = 3

hence the zeroes are :- 1,2,3,

Step-by-step explanation: