Question

P(x) = (x - 1) (x + 3)Find p(0), p(1), p(2) for the above polynomial.

Answer 1

given p(x)=(x-1)(x+3)
p(0)=(0-1)(0+3)
=-3
p(1)=(1-1)(1+3)
=0
p(2)=(2-1)(2+3)
=5
I hope it is helpful

Answer 2

Hi ,

Given p(x) = ( x - 1 )( x + 3 )

1 ) p(0) = ( 0 - 1 )( 0 + 3 ) =(-1)3= -3

2 ) p(1) = ( 1 - 1 )( 1 + 3 ) = 0×3 = 0

3 ) p(2) = ( 2 - 1 )( 2 + 3 ) = 1×5 = 5

Therefore ,

p(0) = -3 ,

p(1) = 0 ,

p(2) = 5

I hope this helps you.

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