Question

p {(x)} = x ^ {2} - 2 \sqrt{2} x + 1 }\\ { \text{Solve for } q \text{ where} } \\ { q = p {(2 \sqrt{2​

Answer 1

Step-by-step explanation:

Simplify: \[\frac{ax-b+x-ab}{a{x}^{2}-abx}, \quad \left(x\ne 0;x\ne b\right)\] ... + q)} \\ & = \frac{(p + q)(p^2 - pq + q^2)}{p^2} \times \frac{3}{p + q} ...