Math, asked by koushalsingh76, 1 year ago

P(X)=(X-2)^2-(X+2)^2​

Answers

Answered by tanha7
2

Answer:

Step-by-step explanation:

using identities =(a+b)^2-(a-b)^2

so,

p(x)=[x-2+x+2][x-2-x-2]

p(x)=2x*-4

p(x)=-8x

now,let -8x=0

so,x=8

Answered by Animeshdas420000
0

Answer:

1/2

Step-by-step explanation:

P(x-2)^2-(x+2)^2

or, (x-2+x+2)(x-2-x+2)=0

or, (2x)(0)=0

or,x=1/2

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