p(x)=x^2-2x-48 find the zeros
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2
Answer:
-6 and 8
Step-by-step explanation:
x^2-8x+6x-48=0
x(x-8)+6(x-8)=0
(x-8)(x+6)=0
x= -6 and x=8
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-6 and 8 is the answer of p(x)=x^2-2x-48
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