Math, asked by utsavtank97, 1 month ago

p(x)=x^2-2x-48 find the zeros​

Answers

Answered by kalpanakaushik0227
2

Answer:

-6 and 8

Step-by-step explanation:

x^2-8x+6x-48=0

x(x-8)+6(x-8)=0

(x-8)(x+6)=0

x= -6 and x=8

Answered by sandmech007
0

-6 and 8 is the answer of p(x)=x^2-2x-48

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