Question

p(x)=x^2_4x+3 find zeroes.Find sum and product of zeroes​

Answer 1

✌️Úr answèr:-✌️

a=1,b=-4 and c=3 [from the eq.]

now,

•sum of zeros (alpha+beta)= -b/a=>-4/1

•product of zeros (alpha*beta)=c/a=>3/1

⬅️Hópé ît helps ü ➡️

Answer 2

step by step explanations:-

➡p(x)= x² - 4x +3

↪. = x² -3x -x + 3

↪. = x(x-3)-1(x-3)

↪. = (x-1)(x-3)

so,

(x-1)=0 or (x-3)=0

↪ x = 1 or , x = 3

➡Sum of zeroes = 1+3

= 4

➡Product of zeroes = 1 × 3

= 3

⏩Hopes its help's u.