Question

p(x)=x^2-4x+3 find zeros

Answer 1

Answer:

3,1

Step-by-step explanation:

          x^2-4x+3=x^2-3x-x+3⇒x=3,x=1

please thanks for answer

Answer 2

$\mathbb\blue{\underline{SOLUTION}}$

$x^{2} - 4x + 3$

$x^{2} - 3x - x + 3$

$x ( x - 3 ) - 1 ( x - 3 )$

$( x - 3 ) ( x - 1 )$

$\mathbb\blue{\underline{ZEROS}}$

• $( x - 3 ) = 0$

$x = 3$

• $( x - 1 ) = 0$

$x = 1$