Question

p(x)= x^2 -7sqrt 7x +3 then p(7sqrt 7) please it's very very urgent

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Answer 1

Answer:

The function f(x)=(x-5)^2+2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the inverse function. a. restricted domain: x>or=5; f^-1(x)=5-sqrt(x-2) b. restricted domain: x>or=5; f^-1(x)=5+sqrt(x-2) c. restricted

Step-by-step explanation:

thx

Answer 2

Step-by-step explanation:

$p(x) = x {}^{2} - 7 \sqrt{7} x + 3 \\ p(7 \sqrt{7} ) = (7 \sqrt{7} ) {}^{2} - 7 \sqrt{7} \times 7 \sqrt{7} + 3 \\ p(7 \sqrt{7} ) = 343 - 343 + 3 \\ so \: \: \: \: \: p(7 \sqrt{7} ) = 3 \: \: \: \: ans.$

HOPE YOU UNDERSTAND.