Question

p[x]=x^2+7x-12 then zeros

Answer 1

Answer:

hloooo

Step-by-step explanation:

middle term split

x^2+3x+4x-12

x(x+3)+4(x+3)

(x+3)(x+4

then the zeroes are -3&-4

Hope it is helpful to you ☺️ and mark me as brainliest plz

Answer 2

Answer:

x^2+7x-12

a= 1, b= 7 and c= 12

Factors of x^2+7x+12

x^2+4x+3x+12

x(x+4) 3(x+4)

(x+4) (x+3)

zeros

(x+4) (x+3) = 0

x= -4, -3

Step-by-step explanation:

Hope this will help you.