Question

p(x) =x+2.find p(1) p(2) p(-1) and(-2) what is the zero of the given polynomial​

Answer 1

Step-by-step explanation:

here is your answer and once try to solve it yourself

Answer 2

The value of p(1) is 3, p(2) is 2, p(-1) is 1, p(-2) is 0, and the zero of the polynomial is -2.

Given,

A polynomial p(x) = x+2.

To Find,

The value of p(1), p(2), p(-1), and p(-2).

Solution,

The given polynomial is

p(x) = x+2

So,

p(1) = 1+2 = 3

p(2) = 2+2 = 4

p(-1) = -1+2 = 1

p(-2) = -2+2 = 0

Now, for the zero of polynomial

p(x) = 0

x+2 = 0

x = -2

Hence, the value of p(1) is 3, p(2) is 2, p(-1) is 1, p(-2) is 0, and the zero of the polynomial is -2.