Question

p(x)=x+2
find p(1),p(2),p(-1)andp(-2)what are the zeros polynomials x+2​

Answer 1

We have to just substitute the vaule of x and simplify in order to simplify and according to the product or final answer we can find the zero of the polynomial .

So the steps go in this way :

• p(x) = x + 2

☞ p(x) = x+2

☞p(1) = 1+2

☞p(1) = 3

• p(x) = x+2

☞p(x) = x+2

☞p(2) = 2+2

☞p(2) = 4

• p(x) = x+2

☞p(x)=x+2

☞ p(-1)= -1+2

☞p(-1) = -1

• p(x) = x+2

☞p(x) = x+2

☞p(-2) = -2+2

☞p(-2)= 0

According to the definition of the zero of the polynomial which says :

Any number which when substituted in the place of x giving the answer as 0 is said to be the zero of the polynomial .

Here in all the solutions we have got only the last one meaning p(-2) is only the zero of the polynomial because no other answers is rendering zero.