Question

P (x)=x+2 find p (1), p (2), p (-1), p (-2) what are the zereos of the polynomial

Answer 1

Answer :

$p(x)=x+2 \\\\ p(1)=1+2=3 \\ p(2)=2+2=4\\p(-1)=-1+2=1\\p(-2)=-2+2=0 \\\\ to \ find \ zero,\\ p(x)=0 \\x+2=0\\x=-2 \\\\ -2 \ is \ zero \ of \ the \ polynomial.$