Math, asked by sharansai42, 10 months ago

p(x)=x^2+px+q find
(Alpha+beta)^2 and (Alpha-beta)^2​

Answers

Answered by laxmita
0

Answer:

hope it helps sssss

Attachments:
Answered by Anonymous
2

Answer:

p(x)=x²+px+q

sum of zeroes=á+ß =-b/a

-> à+ß=-p/1

product of zeroes= åß=c/a

-> åß=q/1

now (å+ß)²= (p/1)² = p²

(à-ß)² = à²+ß²-2àß______1)

using identity to find à²+ß²

[ (à+ß)²= å²+ß²+2åß)]

we get ^

à²+ß²= (à+ß)²-2åß_____2)

= p²+2q

we have value of à+ß (p) & àß (q)

from1)&2)

(à-ß)²= p²-2q-2q

= p²-4q

à-----> alpha

ß-----> beta

Hope it helps you....

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