p(x)=x^2+x-1 find the zeroes of the polynomial please answer fast
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answer of above question .Thank you
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Finding zero of p(x)=(x+1)(x+2), is same as solving the equation p(x)=0.
⇒(x+1)(x+2)=0
⇒(x+1)=0,(x+2)=0
⇒x=−1,−2.
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