Question

p(x)=(x+2)(x+3) solve this

Answer 1

HEY MATE! HERE'S YOUR ANSWER!

p(x) = (x+2)(x+3)

p(x) = x(x+3)+2(x+3)

p(x) = x² + 3x + 2x + 6

p(x) = x² + 5x + 6 ....(i)

Now,

here, 3 and 2 are the zero of the polynomial.

as, x+2 = 0
=> x = -2

and, x+3 = 0
=> x = -3

then,

p(-2) = (-2)² + 5(-2) + 6

p(-2) = 4 - 10 + 6

p(-2) = 10-10

p(-2) = 0 ...... ANSWER.

Also,

p(-3) = (-3)² + 5(-3) + 6

p(-3) = 9 - 15 + 6

p(-3) = 15-15

p(-3) = 0 .....ANSWER.

HOPE IT WAS HELPFUL ✌️!

Answer 2

p(x)=x(x+3)+2(x+3)
p(x)= 2x+3x+2x+6
p(x)=7x+6
p(x)-7x=6
p×(-6x)=6
-6xp=6
xp=6/-6
xp=-1