p(x)=x^3+3x^2 - 2x find p(2) -p (-1) + p(1/2)
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0
Answer :
Given,
p(x) = x³ + 3x² - 2x
So,
p(2) = 2³ + 3 (2²) - 2 (2)
= 8 + 12 - 4
= 16
p(-1) = (- 1)³ + 3 (- 1)² - 2 (- 1)
= - 1 + 3 + 2
= 4
p(1/2)
= (1/2)³ + 3 (1/2)² - 2 (1/2)
= 1/8 + 3/4 - 1
= - 1/8
Therefore, p(2) - p(- 1) + p(1/2)
= 16 - 4 - 1/8
= 95/8
#MarkAsBrainliest
Given,
p(x) = x³ + 3x² - 2x
So,
p(2) = 2³ + 3 (2²) - 2 (2)
= 8 + 12 - 4
= 16
p(-1) = (- 1)³ + 3 (- 1)² - 2 (- 1)
= - 1 + 3 + 2
= 4
p(1/2)
= (1/2)³ + 3 (1/2)² - 2 (1/2)
= 1/8 + 3/4 - 1
= - 1/8
Therefore, p(2) - p(- 1) + p(1/2)
= 16 - 4 - 1/8
= 95/8
#MarkAsBrainliest
Answered by
1
Heya !!!
P(X) = X³+3X² - 2X
P(2) = (2)³ + 3 × (2)² - 2 × 2
=> 8 + 12 - 4
=> 16
P(-1) = (-1)³ + 3 × (-1)² - 2 × -1
=> -1 + 3 + 2
=> 4
And,
P(1/2) = (1/2)³ + 3 × (1/2)² - 2 × 1/2
=> 1/8 + 3 × 1/4 - 1
=> 1/8 + 3/4 - 1
=> 1 + 6 - 8/8
=> -1/8
Therefore,
P(2) - P(-1) + P(1/2)
=> 16 - 4 + (-1/8)
=> 16 - 4 - 1/8
=> 128 - 32- 1/8
=> 128 - 33/8
=> 95/8
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
P(X) = X³+3X² - 2X
P(2) = (2)³ + 3 × (2)² - 2 × 2
=> 8 + 12 - 4
=> 16
P(-1) = (-1)³ + 3 × (-1)² - 2 × -1
=> -1 + 3 + 2
=> 4
And,
P(1/2) = (1/2)³ + 3 × (1/2)² - 2 × 1/2
=> 1/8 + 3 × 1/4 - 1
=> 1/8 + 3/4 - 1
=> 1 + 6 - 8/8
=> -1/8
Therefore,
P(2) - P(-1) + P(1/2)
=> 16 - 4 + (-1/8)
=> 16 - 4 - 1/8
=> 128 - 32- 1/8
=> 128 - 33/8
=> 95/8
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
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