Question

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p(x)= x^3-3x^2-3x+1 by x+1



plz solve this​

Answer 1

HEYAA !!

ANSWER ✏️✏️

$x + 1 = 0 \\ x = - 1 \\ \\ p(x) = {x}^{3} - 3 {x}^{2} - 3x + 1 \\ \\ p( - 1) = (1)^{3} - {3( - 1)}^{2} - 3( - 1) + 1 \\ \: \: \: \: = 1 - 3 + 3 + 1 \\ p( - 1) = 2$

HENCE {x+1} IS NOT A FACTOR OF p(x) AS TGE REMAINDER IS NOT ZERO.

Answer 2

Answer:

p(x)= x^3-3x^2-3x+1

zero of x+1 is -1.

p(x)=(1)^3-3(1)^2-3(1)+1

=3-3-3+1

=0+1

=1

Therefore , x+1 is not a factor of p(x).

DON'T WORRY YOU WILL UNDERSTAND.

HOPE IT WILL HELP YOU.

I UNDERSTAND YOUR PROBLEM BUT WHAT CAN I DO