Question

p(x)=x^3+3x^2+3x+1 ,g(x)=x-1/2
find remainder​

Answer 1

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Answer 2

Step-by-step explanation:

$g(x) = x - \frac{1}{2} = 0 \\ x = \frac{1}{2} \\ \\ p(x) = {x}^{3} + 3 {x}^{2} + 3x + 1 \\ = { (\frac{1}{2}) }^{3} + 3 {( \frac{1}{2} )}^{2} + 3 (\frac{1}{2}) + 1 \\ = \frac{1}{8} + \frac{3}{4} + \frac{3}{2} + 1 \\ = \frac{1 + 6 + 12 + 8}{8} \\ = \frac{27}{8}$