P(x)= x^3+3x^2-5x+7, then P(0) = ?
Answers
Answered by
4
p(0), just put substitute x with 0 and you will get the answer,
p(0)=0³+3(0²)-5(0)+7
=0+0-0+7
=7
∴p(0)=7
p(0)=0³+3(0²)-5(0)+7
=0+0-0+7
=7
∴p(0)=7
Answered by
3
hi there , see the above attachment
Attachments:
Similar questions