Question

P(x)=x^3-ax^2+6x-a,g(x)=x-a

Answer 1

Answer:

$a = 0$

Step-by-step explanation:

$g(x) = x - a$

$x - a = 0$

$x = a$

$P(x)=x^3-ax^2+6x-a$

${a}^{3} - a {(a)}^{2} + 6a - a = 0$

${a}^{3} - {a}^{3} +5a = 0$

$5a = 0$

$a = \frac{0}{5}$

$a = 0$

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