p(x)=x^3+ax^2-x+b
1, find the relationship between a and b for x-2 be a factor of p(x).
2, find the relationship between a and b (x-1), (x-2) are the factors of p(x).
Answers
Answered by
0
Answer:
very tough question, i don't know the answer.
Step-by-step explanation:
strikeact:
no problem.
Answered by
1
Answer:
X³+AX²-X+B
AND , X-2 = 0
==> X = 2
SO, PUTTING VALUE OF X IN POLYNOMIAL
==> (2)³+A(2)²-2+B = 0
==> 8 + 4A-2 + B = 0
==> 6 + 4A + B = 0
==> 4A+B = -6
==> 4A = -6-B
==> A = -6-B/4
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