Math, asked by strikeact, 1 year ago

p(x)=x^3+ax^2-x+b
1, find the relationship between a and b for x-2 be a factor of p(x).
2, find the relationship between a and b (x-1), (x-2) are the factors of p(x).

Answers

Answered by saojidivyanshu5
0

Answer:

very tough question, i don't know the answer.

Step-by-step explanation:



strikeact: no problem.
Answered by thameshwarp9oqwi
1

Answer:


X³+AX²-X+B

AND , X-2 = 0  

==> X = 2

SO, PUTTING VALUE OF X IN POLYNOMIAL

==> (2)³+A(2)²-2+B = 0

==> 8 + 4A-2 + B  = 0

==> 6 + 4A + B = 0

==> 4A+B = -6

==> 4A = -6-B

==> A = -6-B/4


strikeact: brother 2nd question's answer please.
thameshwarp9oqwi: OK
strikeact: knock knock ! answer please!!!
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