p(x)=x^3-ax^2+x is divided by( x-a)
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Answer:
divisor= x-a
quotient= x^2+0
remainder= 0
Step-by-step explanation:
x-a | x^2 + 0
|____________
| x^3 -ax^2+x
| x^3 -ax^2
| (-) (+)
|____________
| 0 0 + x
| x
| (-)
|_____________
| 0
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