Math, asked by ravipal220975, 7 months ago

p(x)=x^3-ax^2+x is divided by( x-a)​

Answers

Answered by amen2711
0

Answer:

divisor= x-a

quotient= x^2+0

remainder= 0

Step-by-step explanation:

x-a | x^2 + 0

|____________

| x^3 -ax^2+x

| x^3 -ax^2

| (-) (+)

|____________

| 0 0 + x

| x

| (-)

|_____________

| 0

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