Math, asked by boienisneha, 1 month ago

p(x)=x+3 then p(0)=?&P(-1)=?​

Answers

Answered by yukhtha2008
0

Step-by-step explanation:

p(y)=y2−y+1

p(0)=(0)2−(0)+1=0+0+1=1

p(1)=(1)2−(1)+1=1−1+1=1

p(2)=(2)2−(2)+1=4−2+1=3

(ii) p(t)=2+t+2t2−t3

p(0)=2+(0)+2(0)2−t3=2+0+0−0=2

p(1)=2+(1)+2(2)2−(1)3=2+1+2−1=4

p(2)=2+(2)+2(2)2−(2)3=2+2+8−8=4

(iii) p(x)=x3

p(0)=(0)3=0

Answered by msgazi96
0

Answer:

p(0)=0+3

p(0)=3

p(-1)=-1+3

p(-1)=2

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