p(x)=x+3 then p(0)=?&P(-1)=?
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Answered by
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Step-by-step explanation:
p(y)=y2−y+1
p(0)=(0)2−(0)+1=0+0+1=1
p(1)=(1)2−(1)+1=1−1+1=1
p(2)=(2)2−(2)+1=4−2+1=3
(ii) p(t)=2+t+2t2−t3
p(0)=2+(0)+2(0)2−t3=2+0+0−0=2
p(1)=2+(1)+2(2)2−(1)3=2+1+2−1=4
p(2)=2+(2)+2(2)2−(2)3=2+2+8−8=4
(iii) p(x)=x3
p(0)=(0)3=0
Answered by
0
Answer:
p(0)=0+3
p(0)=3
p(-1)=-1+3
p(-1)=2
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