Question

p(x)=x^3-x^2-(2+√2)x+√2,g(x)=x+1​

Answer 1

Here's your answer

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x^3-x^2-(2+√2)x+√2, here the value of 'x' is (-1)

{x}^{3} - {x}^{2} - (2 + \sqrt{2} )x + \sqrt{2} \\ = { (- 1)}^{3} - {( - 1)}^{2} - (2 + \sqrt{2} )( - 1)+ \sqrt{2} \\ = ( - 1) - ( + 1) - 2 \times ( - 1) - \sqrt{2} \times ( - 1) + {\sqrt{2} } \\ = - 1 - 1 + 2 + \sqrt{2} + \sqrt{2} \\ = 2 \sqrt{2}

If any problem there then comment here.

Hope it helps!!

Answer 2

Answer:

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