Question

P(x) = x^3 -x^2 +x+1 find p(-1)+p(1)/2

Answer 1

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Answer 2

Hola Mate !!

Here's your answer :-

$p(x) = {x}^{3} - {x}^{2} + x + 1$

$p( - 1) = { - 1}^{3} - ({-1})^{2} + ( - 1) + 1 \\ = - 1 - 1 - 1 + 1 \\ = -2$

$p( \frac{1}{2} ) = ({ \frac{1}{2} })^{3} - ({ \frac{1}{2} })^{2} + \frac{1}{2} - 1 \\ = \frac{1}{8} - \frac{1}{4} + \frac{1}{2} - 1 \\ = \frac{1 - 2 + 4 - 8}{8} \\ = \frac{5 - 10}{8} \\ = \frac{ - 5}{8}$

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