Question

P(x)=(x+3)(x+2)(x+1)
P(x)=(x+2)(x+1)(x-1)(x-2)
P(x)=-(x+1)2^(x-1)(x-2)2^
P(x)=-(x+3)(x+1)(x-2)(x-4)​

Answer 1

Answer:

Correct option is

A

1

B

2

C

3

Finding zero of p(x)=(x−1)(x−2)(x−3), is same as solving the equation p(x)=0.

⇒(x−1)(x−2)(x−3)=0

⇒(x−1)=0,(x−2)=0,(x−3)=0

⇒x=1,2,3.